doodle jump style, player leaves left side of screen en enters smoothly right

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doodle jump style, player leaves left side of screen en enters smoothly right

(7 posts) (5 voices)

Started 7 months ago by yurki
Latest reply from fet_loa

Tags:

doodle jump player sprite left right screen side telepo

yurki
Member

hello!

The effect used in many classic games and also in doodle jump for iphone:
player goes to right end of screen and at the moment he leaves the screen he enters directly the left side of the screen. I want to make this in my game, but don't know what would be the best way. biggest problem, don't know how to look for this on google :S.

does anybody can point me in the right direction? does someone knows the name of this effect?

my idea is to make two player sprites and as soon one goes out of the screen, at the same time the second
goes in on the other side. in the middle there is a point when the second gets invisible and the first gets
visible at the same coordinates. And vica versa.

it seems like a solution, but I'm a bit afraid of getting in to trouble with later coding. I thought maybe there is a more elegant solution...

Posted 7 months ago #
yurki
Member

ok BTW,

I was so sure doodle jump was really smooth in this. But now I see it really isn't.

if it leaves the screen half, it just pops completely on the other side, sticking out
half of the screen there. which is really easy to make...

if (player.position.y > 320 + player.contentSize.height/2) {

player.position = ccp(player.position.x, - player.contentSize.height/2);
}

I guess I never noticed and if you don't notice it's not really worth it to do differently I guess.
Gonne try it out with my game...

Posted 7 months ago #
MikeSz
Member

you can always make 2 sprites for the guy, and in the border scenario show both of them

Posted 6 months ago #
embero
Member

You could just wait that the player sprites leaves the screen ( left + width ) < 0 and put it right onto the other side ( left = screen.width + 1 ),
or use 2 sprite as mentioned by @MikeSz but that could lead to some minor problems ( collision detection, and so on ) which have to be handled right.

Posted 6 months ago #
varedis
Moderator

https://github.com/haqu/tweejump

Posted 6 months ago #
yurki
Member

yes that's what I was afraid of...collision detection and things like that has to be done double for both sprites and all. Not a major problem indeed, it just makes your code a bit more messy.

For now, I made the simple version as seen in doodle jump. Maybe later I make it more smooth. I'm happy for now :)
thanks guy's!

Posted 6 months ago #
fet_loa
Member

It's really not that difficult as I see it. Use two sprites, place them one screen width apart.

Just make sure the sprite that is not currently showing on screen is on the correct side (let or right). A sprite is considered to be off screen when it has pos.x > (screenwidth + sprite.size.width) or pos.x < -sprite.size.width.

Double collision detection shouldn't be too messy either, two function calls instead of one, and not that expensive, unless you use a physics engine in which case there is basically no difference from doing collision detection for one object.

Posted 6 months ago #

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